Answer: (15, 10) minutes

Explanation:
Let x be the time in minutes required by pipe A to fill the tank, and y minutes be the time required by pipe B to fill the tank. Also, let pipe A take 5 minutes more than pipe B to fill up the tank.
Therefore, x = y + 5
1/x + 1/y = 1/6
Also, 1/x = 1/(y + 5)
1/(y + 5) + 1/y = 1/6
6*(y + y + 5) = (y + 5)*y
12y + 30 = y2 + 5y
y2 – 7y – 30 = 0
y = 10
x = 15

Answer: 48 hours

Explanation:
As the inlet can fill the tank in 12 hours, in one hour it will fill 1/12th of the tank.
Similarly, the outlet pipe in one hour can empty 1/16th part of the tank.
If both are opened simultaneously, the part of the tank filled in one hour is:
1/12 - 1/16 = 1/48
Hence, the tank gets filled in 48 hours.

Answer: 4800 litres

Explanation:
The capacity of the tank is given by C = (p*q*r)/(r – p) litres
Where, p = time in which the leakage can empty the tank in hours = 5 hours
q = rate at which the inlet fills the tank in lph = 6*60 = 360 lph
r = time in which the tank gets emptied in hours = 8 hours
Hence, C = (5*360*8)/(8 – 5)
C = 4800 litres

Answer: 12

Explanation:
a pipe takes x hours to fill a tank and another takes y hours to fill it,
=>In xy / x + y hours
=> In this problem, x = 20 and y = 30
=> xy / x + y = 12

Answer: 15

Explanation:
Let us say pipe X should be closed after n minutes.
=> i.e. pipe X is in operation for n minutes and pipe Y for all the 30 minutes
=> So, n/30 + 30/60 = t
n = 15

Answer: 3240 litres

Explanation:
Explanation: Let the time that would be taken by the leak to empty the full tank be
=>  x hours ,
=> 1/6 – 1/x = 1/18
=> x = 9
Capacity of the tank = (6) (9) (60) = 3240 litres

Answer: 35 hours

Explanation:

Answer: 14 min. 40 sec.

Explanation:

Answer: 30 min

Explanation:

Answer: 7 hours

Explanation: